Question: Solve the following initial value problems. y' 1 = y 1 + 3y 2 y' 2 = 1/3y 1 + y 2 y 1 (0)

Solve the following initial value problems.

y'1 = y1 + 3y2

y'2 = 1/3y 1 + y2

y1(0) = 12, y2(0) = 2

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