Let A be a one-dimensional vector space over the rational field Q. If we define ab =
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Let A be a one-dimensional vector space over the rational field Q. If we define ab = 0 for all a,b ϵ A, then A is a Q-algebra. Every proper additive subgroup of A is an ideal of the ring A, but not an algebra ideal.
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Since A is a onedimensional vector space over Q it has a basis consisting of a single element say 1 ...View the full answer
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Related Book For
Algebra Graduate Texts In Mathematics 73
ISBN: 9780387905181
8th Edition
Authors: Thomas W. Hungerford
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