Let {N i | i I| be a family of subgroups of a group G. Then

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Let {Ni| i ϵ I| be a family of subgroups of a group G. Then G is the internal weak direct product of {Ni| i ϵ I} if and only if: (i) ai,ai = aiai for all i ≠ j and ai ϵ Ni, ai ϵ Ni; (ii) every nonidentity element of G is uniquely a product ai1 • • • ain where i1, ... , in are distinct elements of I and e ≠ c aik ϵ Nik for each k. [Compare Theorem 8.9.]

Data From Theorem 8.9

Theorem 8.9.

Let { Ni| i ϵ I| be a family of normal subgroups of a group G. G is the internal weak direct product of the family { Ni| i ϵ I| if and only if every nonidentity element of G is a unique product ai1ai2 • • • ain with i1, ... , in distinct elements of I and e ≠ aik ϵ Nik for each k = 1,2, ... , n.

PROOF.

Exercise. ■
There is a distinction between internal and external weak direct products. If a group G is the internal weak direct product of groups Ni, then by definition each Ni is actually a subgroup of G and G is isomorphic to the external weak direct product 

However, the external weak direct product 

does not actually contain the groups Ni, but only isomorphic copies of them (namely the L1(Ni)- see Theorem 8.4 and Exercise 10). Practically speaking, this distinction is not very important and the adjectives "internal .. and "external .. will be omitted whenever no confusion is possible. In fact we shall use the following notation.

NOTATION.

We write  

to indicate that the group G is the internal weak direct product of the family of its subgroups {Ni|i ϵ I|.

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