(a) Differentiating, we have k'(x) = 3x 2 1, so For the functions in Problems (a)...
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(a) Differentiating, we have k'(x) = 3x2 − 1, so For the functions in Problems (a) Find the derivative at x = −1.
(b) Find the second derivative at x = −1.
(c) Use your answers to parts (a) and (b) to match the function to one of the graphs in Figure 3.10, each of which is shown centered on the point (−1, −1).
k(x) = x3 − x − 1
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a Differentiating we have kx 3x 2 1 so b Taking ...View the full answer
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Related Book For 
Applied Calculus
ISBN: 9781119275565
6th Edition
Authors: Deborah Hughes Hallett, Patti Frazer Lock, Andrew M. Gleason, Daniel E. Flath, Sheldon P. Gordon, David O. Lomen, David Lovelock, William G. McCallum, Brad G. Osgood, Andrew Pasquale
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