Question: Figure 9 contains the graph of the function f (x) = x 3 - 12x. The function has zeros at x = -12, 0, and

Figure 9 contains the graph of the function f (x) = x³ - 12x. The function has zeros at x = -√12, 0, and √12. Which zero of f(x) will be approximated by the Newton–Raphson method starting with x₀ = 4? Starting with x₀ = 1? Starting with x₀ = -1.8? -4 12 + -2 20 y 10. -10 12 + 2 4

-4 12 + -2 20 y 10. -10 12 + 2 4 -20+ Figure 9 Graph of f(x) = x - 12x. x

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