Question: If y 0 > 1, is the solution y = f (t) of the initial-value problem y = 2y (1 - y), y (0) =

If y0 > 1, is the solution y = f (t) of the initial-value problem y′ = 2y (1 - y), y (0) = y0, decreasing for all t > 0? Answer this question based on the slope field shown in Fig. 8.

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