Question: Suppose that the interval 0 t 3 is divided into 1000 subintervals of width t. Let t 1 , t 2 ,....., t

Suppose that the interval 0 ≤ t ≤ 3 is divided into 1000 subintervals of width Δt. Let t1, t2,....., t1000 denote the right endpoints of these subintervals. If we need to estimate the sume-0.111000 1, 5000-0.14. + 5000 -0.112 1 + ... + 5000e-

show that this sum is close to 13,000.

e-0.111000 1, 5000-0.14. + 5000 -0.112 1 + ... + 5000e-

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