Question: The following nonlinear differential equation was solved in Examples 24.4 and 24.7. Such equations are sometimes linearized to obtain an approximate solution. This is done

The following nonlinear differential equation was solved in Examples 24.4 and 24.7.


0= +h' (ToT) +o' (T - T4) dT dx (P24.5)


Such equations are sometimes linearized to obtain an approximate solution. This is done by employing a first-order Taylor series expansion to linearize the quartic term in the equation as


image


where T is a base temperature about which the term is linearized. Substitute this relationship into Eq. (P24.5), and then solve the resulting linear equation with the finite difference approach. Employ T = 300, Δx = 1m, and the parameters from Example 24.4 to obtain your solution. Plot your results along with those obtained for the nonlinear versions in Examples 24.4 and 24.7.

In Example 24.4:

Although it served our purposes for illustrating the shooting method, Eq. (24.6) was not a completely realistic model for a heated rod. For one thing, such a rod would lose heat by mechanisms such as radiation that are nonlinear.

Suppose that the following nonlinear ODE is used to simulate the temperature of the heated rod:

image

where σ′ = a bulk heat-transfer parameter reflecting the relative impacts of radiation and conduction = 2.7 × 10−9 K−3 m−2 . This equation can serve to illustrate how the shooting method is used to solve a two-point nonlinear boundary-value problem. The remaining problem conditions are as specified in Example 24.2: L = 10 m, h′ = 0.05 m−2 , T = 200 K, T(0) = 300 K, and T(10) = 400 K.

In Example 24.7:

Use the finite-difference approach to simulate the temperature of a heated rod subject to both convection and radiation:

image

where σ′ = 2.7 × 10−9 K−3m−2 , L = 10 m, h′ = 0.05 m−2 ,T = 200 K,T(0) = 300 K, andT(10) = 400 K. Use four interior nodes with a segment length of Δx = 2 m.

0= +h' (ToT) +o' (T - T4) dT dx (P24.5)

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