Find the voltage drop across R5 in Fig. 17.82. Figure 17.82 R = 4.35 02 WWWR =
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Find the voltage drop across R5 in Fig. 17.82.
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Figure 17.82 R₁ = 4.35 02 WWWR₁ = 0.765 2 www Lw www R₂ = 3.750 TE= 75.5 V R₂ = 1.56 02 www R₂ = 3.42 02
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R1 and R2 are in parallel connection so total of those R p 435 1 ...View the full answer
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Applied Physics
ISBN: 978-0134159386
11th Edition
Authors: Dale Ewen, Neill Schurter, Erik Gundersen
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Find the voltage drop across R1 in Fig. 17.82. Figure 17.82 R = 4.35 02 WWWR = 0.765 2 www Lw www R = 3.750 ww R = 1.56 02 TE= 75.5 V www R = 3.42 02
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