Question: =+84. Consider the situation described in Exercise 83. a. What is P(x1 , , x2 . , x3 . ,, xn . ), that is,

=+84. Consider the situation described in Exercise 83.

a. What is P(x1 , , x2 . , x3 . ,…, xn . ), that is, the probability that only the first observation is smaller than the median and all others exceed the median?

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