Question: A testing station found p parts per million (ppm) of sulfur dioxide in the air as a function of the hour h of the day

A testing station found p parts per million (ppm) of sulfur dioxide in the air as a function of the hour h of the day to be p = 0.00174(10 + 24h − h2). Sketch the graph of p = f (h) and, from the graph, find the time when p = 0.205 ppm.

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To sketch the graph of p fh we can plot the function for various values of h and connect the points ... View full answer

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