Answer the given questions related to the indicated examples of this section.

In Example 1, if widths of the face of the same cam were given at 1.00-cm intervals (five more widths would be included), from the methods of this section, what is probably the most accurate way of finding the area? Explain.

Data from Example 1.

A plate cam for opening and closing a valve is shown in Fig. 2.99. Widths of the face of the cam are shown at 2.00-cm intervals from one end of the cam. Find the area of the face of the cam.

From the figure, we see that

(In making such measurements, often a y-value at one end—or both ends—is zero. In such a case, the end “trapezoid” is actually a triangle.) From the given information in this example, h = 2.00 cm. Therefore, using the trapezoidal rule, Eq. (2.12), we have

The area of the face of the cam is approximately 26.3 cm².

Yo = 2.56 cm Y3 2.95 cm Y = Y4 3.82 cm 1.85 cm 1/ = Y5 3.25 cm 0.00 cm