Question: For a radioactive isotope, the constant of proportionality k is given by Cobalt-60, used in cancer therapy, has a halflife of 5.27 years. What is

For a radioactive isotope, the constant of proportionality k is given by 

k = log, (2) half-life


Cobalt-60, used in cancer therapy, has a halflife of 5.27 years. What is the value of k?

k = log, (2) half-life

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ANSWER The given formula for k is k ln2 halflife Where ... View full answer

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