Question: For a radioactive isotope, the constant of proportionality k is given by Cobalt-60, used in cancer therapy, has a halflife of 5.27 years. What is
For a radioactive isotope, the constant of proportionality k is given by

Cobalt-60, used in cancer therapy, has a halflife of 5.27 years. What is the value of k?
k = log, (2) half-life
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ANSWER The given formula for k is k ln2 halflife Where ... View full answer
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