Question: If a rocket is launched with an initial velocity of 320 ft/s, its height above ground after t seconds is given by 16t 2 +

If a rocket is launched with an initial velocity of 320 ft/s, its height above ground after t seconds is given by −16t² + 320t (in ft). Find the times when the height is 0.

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To find the times when the height of the rocket is 0 we need to solve the equation 16t2 320t 0 ... View full answer

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