Question: In an experiment, an object is allowed to fall, stop, and then fall for twice the initial time. The total distance the object falls is
In an experiment, an object is allowed to fall, stop, and then fall for twice the initial time. The total distance the object falls is 45 ft. The equations relating the times t1 and t2 (in s) of fall are 16t12 + 16t22 = 45 and t2 = 2t1 Find the times of fall.
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Let t1 be the initial time of fall According to the problem ... View full answer
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