Question: In Example 3(a), change 1/2 to 1. Data from Example 3(a) This is the only value of the function that lies within the defined range.
In Example 3(a), change 1/2 to −1.
Data from Example 3(a)

This is the only value of the function that lies within the defined range. The value 5π/6 is not correct, even though sin(5π/6) = 1/2. Since 5π/6 lies outside the defined range.
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To change 12 to 1 in Example 3a we need to find the angle whose sine ... View full answer
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