In Example 6(c), change the 5 on the right side of the equation to −5 and then solve.

Data from Example 6(c)

What values of x and y satisfy the equation x + 3(xj + y) = 5 − j − jy ?

Rewriting each side in the form a + bj, and equating real parts and equating imaginary parts, we have (x + 3y) + 3xj = 5 + (−1 − y) j 

For equality, x + 3y = 5 and 3x = −1 − y. The solution of this system of equations is x = −1 and y = 2.