The amount A of cesium 137 (a dangerous radioactive element) remaining after t years is given by A A 0 (0 5 t 30 3 ),where A 0 is the initial amount In what year will the cesium 137 be 10 of that released at the Chernobyl disaster in 1986

Question: The amount A of cesium-137 (a dangerous radioactive element) remaining after t years is given by A = A 0 (0.5 t/30.3 ),where A 0

The amount A of cesium-137 (a dangerous radioactive element) remaining after t years is given by A = A₀ (0.5^t/30.3),where A₀is the initial amount. In what year will the cesium-137 be 10% of that released at the Chernobyl disaster in 1986?

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