The length L (in ft) of a cable hanging between equal supports 100 ft apart is L 100(1 0 0003s 2 ), where s is the sag (in ft) in the middle of the cable Because L f (s), find f(15) ...

ANSWER The formula given is L 1001 00003s2 where s is the sag in ft in the midd ...

The length L (in ft) of a cable hanging between equal supports 100 ft apart is L

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The length L (in ft) of a cable hanging between equal supports 100 ft apart is L = 100(1 + 0.0003s²), where s is the sag (in ft) in the middle of the cable. Because L = f (s), find f(15).

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Basic Technical Mathematics

ISBN: 9780137529896

12th Edition

Authors: Allyn J. Washington, Richard Evans

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Question Posted: Mar 18, 2023 06:48 AM

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The length L (in ft) of a cable hanging between equal supports 100 ft apart is L

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Basic Technical Mathematics

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