The length L (in ft) of a cable hanging between equal supports 100 ft apart is L 100(1 0 0003s 2 ), where s is the sag (in ft) in the middle of the cable Because L f (s), find f(15)

Question: The length L (in ft) of a cable hanging between equal supports 100 ft apart is L = 100(1 + 0.0003s 2 ), where s

The length L (in ft) of a cable hanging between equal supports 100 ft apart is L = 100(1 + 0.0003s²), where s is the sag (in ft) in the middle of the cable. Because L = f (s), find f(15).

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ANSWER The formula given is L 1001 00003s2 where s is the sag in ft in the midd... View full answer

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