Question: Three electric capacitors are connected in series. The capacitance of the second is 1F more than the first, and the third is 2F more than

Three electric capacitors are connected in series. The capacitance of the second is 1μF more than the first, and the third is 2μF more than the second. The capacitance of the combination is 1.33μF. The equation used to determine C, the capacitance of the first capacitor, is

C + + C+3 34

Find the values of the capacitances.

C + + C+3 34

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When capacitors are connected in series the total capacitance is given by 1C 1C1 1C2 1C3 where C1 C2 ... View full answer

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