Question: Repeat Exercise 16, using the alternative Jeffreys noninformative prior (see Subsection 3.3.3) (, ) = 31(0.)(). (This corresponds to (0, 0) = 02I(0,0) (o) for

Repeat Exercise 16, using the "alternative Jeffreys noninformative prior" (see Subsection 3.3.3)

π(θ, σ²) = σ31(0.)(σ²).

(This corresponds to "(0, 0) = 02I(0,0) (o) for σ.) Do the two noninformative priors give similar answers?

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