Suppose that the standard test statistic z = (X- 0 )/(/n) takes the value z =
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Suppose that the standard test statistic z = (X̅- θ0)/√(ϕ/n) takes the value z = 2.5 and that the sample size is n = 100. How close to θ0 does a value of θhave to be for the value of the normal likelihood function at X̅ to be within 10% of its value at θ = θ0?
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The normal likelihood function is given by L0 where is the sample mean is the parame...View the full answer
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