Suppose that the standard test statistic z (X 0 ) ( n) takes the value z 2 5 and that the sample size is n 100 How close to 0 does a value of have to be for the value of the normal likelihood function at X to be within 10 of its value at 0

Question: Suppose that the standard test statistic z = (X- 0 )/(/n) takes the value z = 2.5 and that the sample size is n

Suppose that the standard test statistic z = (X̅- θ₀)/√(ϕ/n) takes the value z = 2.5 and that the sample size is n = 100. How close to θ₀ does a value of θhave to be for the value of the normal likelihood function at X̅ to be within 10% of its value at θ = θ₀?

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