Question: Exercise 2.14 (Chebyshevs Inequality) Suppose that a random variable X has the mean = E[X] and the variance 2 = V[X]. For any
Exercise 2.14 (Chebyshev’s Inequality) Suppose that a random variable X has the mean μ = E[X] and the variance σ2 = V[X]. For any ε > 0, prove that

Hint: Use Markov’s inequality with h(x) = (x − μ)2 and a = ε2.
P{|X->}
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