Question: Exercise 2.5 (Bayes Formula) In the same notation as in (2.6), prove that P(A|B) i=1 P(Ak)P(B|Ak) P(A)P(BA;)

Exercise 2.5 (Bayes Formula) In the same notation as in (2.6), prove that

P(A|B) i=1 P(Ak)P(B|Ak) P(A)P(BA;)

P(A|B) i=1 P(Ak)P(B|Ak) P(A)P(BA;)

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