Question: When the code that follows runs on an ArrayList of String s, it throws an exception. Why? for (String s: words) { System.out.println (s); if
When the code that follows runs on an ArrayList of String s, it throws an exception. Why?

for (String s: words) { System.out.println (s); if (s.equals ("hello")) { words.add ("goodbye"); }
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The code throws a Concurrent... View full answer
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