Question: Let and Show that is continuous, but not differentiable, at x = 0. Show that g is differentiable at 0, and find g'(0). f(x)

Letf(x) = x sin in / 0, x #0 x = 0andShow that ƒ is continuous, but not differentiable, at x = 0.

Show that g is differentiable at 0, and find g'(0).

f(x) = x sin in / 0, x #0 x = 0

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fx fx sin1x x 0 x 0 Using the Squeeze Theorem you have x x sin1x ... View full answer

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