When evaluating x sin x dx, explain how letting u = sin x and dv = x

Question:

When evaluating ∫x sin x dx,
explain how letting u = sin x and dv = x dx makes the
solution more difficult to find.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Calculus

ISBN: 9781285057095

10th Edition

Authors: Ron Larson, Bruce H. Edwards

Question Posted: