A hot anvil with cooling constant k = 0.02 s 1 is submerged in a large pool
Question:
A hot anvil with cooling constant k = 0.02 s−1 is submerged in a large pool of water whose temperature is 10°C. Let y(t) be the anvil’s temperature t seconds later.
(a) What is the differential equation satisfied by y(t)?
(b) Find a formula for y(t), assuming the object’s initial temperature is 100°C.
(c) How long does it take the object to cool down to 20°?
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a By Newtons Law of Cooling the differential equation is y 002y 10 b The ge...View the full answer
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