Question: A projectile is launched from ground level with an initial velocity 0 at an angle , where 0 /2. Its horizontal

A projectile is launched from ground level with an initial velocity νat an angle θ, where 0 ≤ θ ≤ π/2. Its horizontal range is R = (2v20/g) sinθ cos θ, where g = 32 ft/s2 with  ν0 in ft/s, and g = 9.8 m/s2 with νin m/s. Calculate dR/dθ. The maximum range occurs where dR/dθ = 0. Show that that occurs at θ = π/4 and that the maximum range is v20/g.

Step by Step Solution

3.40 Rating (163 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

Let R 2v 2 0 g sin cos Then Setting dRd 0 yields ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Calculus 4th Questions!