A projectile is launched from ground level with an initial velocity 0 at an angle ,
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A projectile is launched from ground level with an initial velocity ν0 at an angle θ, where 0 ≤ θ ≤ π/2. Its horizontal range is R = (2v20/g) sinθ cos θ, where g = 32 ft/s2 with ν0 in ft/s, and g = 9.8 m/s2 with ν0 in m/s. Calculate dR/dθ. The maximum range occurs where dR/dθ = 0. Show that that occurs at θ = π/4 and that the maximum range is v20/g.
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Let R 2v 2 0 g sin cos Then Setting dRd 0 yields ...View the full answer
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