Assume that exists and (x) = 0 for all x. Prove that (x) = mx +
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Assume that ƒ" exists and ƒ"(x) = 0 for all x. Prove that ƒ(x) = mx + b, where m = ƒ'(0) and b = ƒ(0).
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Let fx 0 for all x Then fx constant for all x Since f0 m we c...View the full answer
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