Assume that the outside temperature varies as T(t) = 15 + 5 sin(t/12) where t = 0
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Assume that the outside temperature varies as T(t) = 15 + 5 sin(πt/12) where t = 0 is 12 noon. A house is heated to 25°C at t = 0 and after that, its temperature y(t) varies according to Newton’s Law of Cooling (Figure 6):
Data From Exercise 45
Let a, b, r be constants. Show that
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dy = dt = -0.1(y(t) - T(t))
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The differential equation is dy dt This differential equation is of the ...View the full answer
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