Compute the critical points of h(t) = (t 2 1) 1/3 . Check that your answer
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Compute the critical points of h(t) = (t2 − 1)1/3. Check that your answer is consistent with Figure 20. Then find the extreme values of h on [0, 1] and on [0, 2].
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-2 - 1 h(t) 1- -1 1 2
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2t Let ht t113 Then ht 31123 consistent with Figure 20 which shows a ...View the full answer
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