Question: Figure 6 shows that (x) = x 3 8x 1 has a root in the interval [2.75, 3]. Apply the Bisection Method twice

Figure 6 shows that ƒ(x) = x³− 8x − 1 has a root in the interval [2.75, 3]. Apply the Bisection Method twice to find an interval of length 1/16 containing this root.

Aud 1 2 3 FIGURE 6 Graph of y = x8x - 1. -X

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