Find the extreme values on the interval. (x) = 4x tan 2 x, [/4, /3]
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Find the extreme values on the interval.
ƒ(x) = 4x − tan2 x, [−π/4, π/3]
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Let fx 4x tanx Then fx 4 2 tan x sec x and fx 0 when tan x secx 2x is clearly ...View the full answer
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