Find the intervals on which is concave up or down, the points of inflection, the critical
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Find the intervals on which ƒ is concave up or down, the points of inflection, the critical points, and the local minima and maxima.
ƒ(x) = x5/3 − x
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Let fx x3 x Then fxx3 1 0 yields x 3 2 as a candidate for an extremum Moreover fxx13 whi...View the full answer
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