Find the surface area of the portion (S) of the cone (z^{2}=x^{2}+y^{2}), where (z geq 0), contained
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Find the surface area of the portion \(S\) of the cone \(z^{2}=x^{2}+y^{2}\), where \(z \geq 0\), contained within the cylinder \(y^{2}+z^{2} \leq 1\).
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We rewrite the equation of the cone as x pm sqrtz2y2 The projection of the cone onto the y z plane i...View the full answer
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