Question: Give an example of a (discontinuous) function that does not satisfy the conclusion of the IVT on [1, 1]. Then show that the function satisfies

Give an example of a (discontinuous) function that does not satisfy the conclusion of the IVT on [−1, 1]. Then show that the function

f(x) = - sin- 0 X # 0 x = 0

satisfies the conclusion of the IVT on every interval [−a, a].

f(x) = - sin- 0 X # 0 x = 0

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