Question: If 0 (x) g(x) for x in the interval [a, b], can the surface obtained by rotating the graph of y = g(x)

If 0 ≤ ƒ(x) ≤ g(x) for x in the interval [a, b], can the surface obtained by rotating the graph of y = g(x) around the x-axis over the interval have less surface area than the surface obtained by rotating the graph of y = ƒ(x) around the x-axis over the same interval?

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