Question: In Exercises 17 and 18, let y(t) be a solution of the logistic equation where A > 0 and k > 0. (a) Differentiate Eq.

In Exercises 17 and 18, let y(t) be a solution of the logistic equation

dt = ky(1 A

where A > 0 and k > 0.

(a) Differentiate Eq. (9) with respect to t and use the Chain Rule to show that

( x - ) 4 = 7/1

d=2(1-2)(1-2) 2y A

(b) Show that the graph of the function y is concave up if 0 < y < A/2 and concave down if A/2 < y < A. (c)

dt = ky(1 A

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