In this exercise, we show that the orthogonal distance D from the plane P with equation ax

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In this exercise, we show that the orthogonal distance D from the plane P with equation ax + by + cz = d to the origin O is equal to (Figure 11)

D = |d| a + b + c

Let n = (a, b, c), and let P be the point where the line through the origin with direction vector n

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Calculus

ISBN: 9781319055844

4th Edition

Authors: Jon Rogawski, Colin Adams, Robert Franzosa

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Question Posted: Jan 03, 2024 07:05 AM

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In this exercise, we show that the orthogonal distance D from the plane P with equation ax

Question:

D = |d| a + b + c

Step by Step Answer:

Let v be the vector v d nn n Then v is parallel to n an...View the full answer

Calculus

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