Question: Let Set y = mx and show that the resulting limit depends on m, and therefore the does not exist. f(x,y) = 2x + 3y

Let f(x,y) = 2x + 3ySet y = mx and show that the resulting limit depends on m, and therefore theĀ limit lim f(x,y) (x,y) (0,0)does not exist.

f(x,y) = 2x + 3y

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We have fx mx 2x 3mx 3m 2x mx m 2 m 1 xmx So f is constant ... View full answer

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