Let (x) = 2x 2 3x 5. Show that the secant line through (2, (2)) and (2 + h, (2 + h)) has

Let ƒ(x) = 2x² − 3x − 5. Show that the secant line through (2, ƒ(2)) and (2 + h, ƒ(2 + h)) has slope 2h + 5. Then use this formula to compute:

(a) The slope of the secant line through (2, ƒ(2)) and (3, ƒ(3))
(b) The slope of the tangent line at x = 2 (by taking a limit)