Question: Let (x) = x 2 . Show that the center of the osculating circle at (xo, x) is given by (-4x, + 3x).
Let ƒ(x) = x2. Show that the center of the osculating circle at ![]()
(xo, x) is given by (-4x, + 3x).
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We parametrize the curve by rx xx The center Q of the osculating cir... View full answer
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