Question: Show that the Maclaurin polynomials for (x) = sin x are T2n+1(x) = T2n+2(x) = x- - x 3! + 5! 2n+1 (2n + 1)!

Show that the Maclaurin polynomials for ƒ(x) = sin x are

T2n+1(x) = T2n+2(x) = x= - x 3! + 5! 2n+1 (2n + 1)! + (1)"-

T2n+1(x) = T2n+2(x) = x- - x 3! + 5! 2n+1 (2n + 1)! + (1)"-

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