Show that the slope of the secant line for (x) = x 3 2x over [5,
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Show that the slope of the secant line for ƒ(x) = x3 − 2x over [5, x] is equal to x2 + 5x + 23. Use this to estimate the slope of the tangent line at x = 5.
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Let fx x 2x The slope of the secant line over the interval 5 x is fxf5 x...View the full answer
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