Question: The area function F(x) = x 0 1 t 2 dt is an antiderivative of (x) = 1 x 2 . Prove

The area function F(x) = ∫x 0 √1 − t2 dt is an antiderivative of ƒ(x) = √1 − x2. Prove the formula

1 1 *VI-Pdt = sin x + x V - Vi 2 S 0

using geometry by interpreting the integral as the area of part of the unit circle.


1 1 *VI-Pdt = sin x + x V - Vi 2 S 0

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