The series 1 +(1/5) + (1/5) 2 + (1/5) 3 + converges to 5/4.
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The series 1 +(1/5) + (1/5)2 + (1/5)3 + · · · converges to 5/4. Calculate SN for N = 1, 2, . . . until you find an SN that approximates 5/4 with an error less than 0.0001.
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Note that S 1 S 1 S3 1 S3 1 S4 1 S5 1 1 5 115 ...View the full answer
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