Question: Use Eq. (2) to evaluate cosh 4 x dx. +=1 / cosh-2 x dx 71 [cosh xdx==cosh 1x sinh x +

Use Eq. (2) to evaluate ∫ cosh4 x dx.

+"=1 / cosh"-2 x dx 71 [cosh" x dx ==cosh" 1x sinh x + ?


+"=1 / cosh"-2 x dx 71 [cosh" xdx==cosh" 1x sinh x +

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