Question: Use Eq. (6) to find dy/dx at the given point. (sin 2, cos 3), = /6 dy dx dy/dt dx/dt y' (t) x' (t)

Use Eq. (6) to find dy/dx at the given point.

dy_dy/dt dx/dt dx y' (t) x' (t)

(sin 2θ, cos 3θ), θ = π/6

dy dx dy/dt dx/dt y' (t) x' (t)

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