Question: We wish to define the average value Av ( f ) Av ( f ) of a continuous function f f along a curve

We wish to define the average value Av(f) of a continuous function f along a curve C of length L. Divide C into N consecutive arcs C1,,CN, each of length L/N, and let Pi be a sample point in Ci (Figure 26). The sum

1Ni=1f(Pi)
may be considered an approximation to Av(f), so we define
Av(f)=limN1Ni=1f(Pi)
Prove that
Av(f)=1LCf(x,y,z)ds
Show that LNi=1f(Pi) is a Riemann sum approximation to the line integral of f along C.

P2 Pi Ci Curve C PN X

P2 Pi Ci Curve C PN X

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The Riemann sum approximation to the line integral is sumi1N fleftPiight Delta Si If the c... View full answer

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